4sin(2x)+4cos^2(2x)=0

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Solution for 4sin(2x)+4cos^2(2x)=0 equation:


Simplifying
4sin(2x) + 4cos2(2x) = 0

Remove parenthesis around (2x)
4ins * 2x + 4cos2(2x) = 0

Reorder the terms for easier multiplication:
4 * 2ins * x + 4cos2(2x) = 0

Multiply 4 * 2
8ins * x + 4cos2(2x) = 0

Multiply ins * x
8insx + 4cos2(2x) = 0

Remove parenthesis around (2x)
8insx + 4cos2 * 2x = 0

Reorder the terms for easier multiplication:
8insx + 4 * 2cos2 * x = 0

Multiply 4 * 2
8insx + 8cos2 * x = 0

Multiply cos2 * x
8insx + 8cos2x = 0

Reorder the terms:
8cos2x + 8insx = 0

Solving
8cos2x + 8insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8insx' to each side of the equation.
8cos2x + 8insx + -8insx = 0 + -8insx

Combine like terms: 8insx + -8insx = 0
8cos2x + 0 = 0 + -8insx
8cos2x = 0 + -8insx
Remove the zero:
8cos2x = -8insx

Divide each side by '8os2x'.
c = -1ino-1s-1

Simplifying
c = -1ino-1s-1

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